Enter a problem...
Finite Math Examples
7x47x4 , 5x25x2
Step 1
Since 7x4,5x27x4,5x2 contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part 7,57,5 then find LCM for the variable part x4,x2x4,x2.
Step 2
The LCM is the smallest positive number that all of the numbers divide into evenly.
1. List the prime factors of each number.
2. Multiply each factor the greatest number of times it occurs in either number.
Step 3
Since 77 has no factors besides 11 and 77.
77 is a prime number
Step 4
Since 55 has no factors besides 11 and 55.
55 is a prime number
Step 5
The LCM of 7,57,5 is the result of multiplying all prime factors the greatest number of times they occur in either number.
5⋅75⋅7
Step 6
Multiply 55 by 77.
3535
Step 7
The factors for x4x4 are x⋅x⋅x⋅xx⋅x⋅x⋅x, which is xx multiplied by each other 44 times.
x4=x⋅x⋅x⋅xx4=x⋅x⋅x⋅x
xx occurs 44 times.
Step 8
The factors for x2x2 are x⋅xx⋅x, which is xx multiplied by each other 22 times.
x2=x⋅xx2=x⋅x
xx occurs 22 times.
Step 9
The LCM of x4,x2x4,x2 is the result of multiplying all prime factors the greatest number of times they occur in either term.
x⋅x⋅x⋅xx⋅x⋅x⋅x
Step 10
Step 10.1
Multiply xx by xx.
x2⋅x⋅xx2⋅x⋅x
Step 10.2
Multiply x2x2 by xx by adding the exponents.
Step 10.2.1
Multiply x2x2 by xx.
Step 10.2.1.1
Raise xx to the power of 11.
x2⋅x1⋅xx2⋅x1⋅x
Step 10.2.1.2
Use the power rule aman=am+naman=am+n to combine exponents.
x2+1⋅xx2+1⋅x
x2+1⋅xx2+1⋅x
Step 10.2.2
Add 22 and 11.
x3⋅xx3⋅x
x3⋅xx3⋅x
Step 10.3
Multiply x3x3 by xx by adding the exponents.
Step 10.3.1
Multiply x3x3 by xx.
Step 10.3.1.1
Raise xx to the power of 11.
x3⋅x1x3⋅x1
Step 10.3.1.2
Use the power rule aman=am+naman=am+n to combine exponents.
x3+1x3+1
x3+1x3+1
Step 10.3.2
Add 33 and 11.
x4x4
x4x4
x4x4
Step 11
The LCM for 7x4,5x27x4,5x2 is the numeric part 3535 multiplied by the variable part.
35x435x4